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Proof step 5 from proof union-at-left (previous step)

⊦ (st ∪ st0)[rk] = st[rk], rk ∈ st0

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ st ∪ ∅ = st
Proof step 4:
∀ st, rk. (st ∪ st1)[rk] = st[rk] ∨ rk ∈ st1 ⊦ (st ∪ st1[rk0, val])[rk] = st[rk], rk ∈ st1[rk0, val]

Rule argument

[VARWITHVARSEQSARG : st0, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : store generated by ∅, [];])]]