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Proof step 8 from proof union-at-right-01 (previous step)

rk ∈ st0 ⊦ (st ∪ st0)[rk] = st0[rk]

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ st ∪ ∅ = st
Proof step 2:
⊦ ∅[rk] = noval
Proof step 7:
∀ rk, st. rk ∈ st1 → (st ∪ st1)[rk] = st1[rk], rk ∈ st1[rk0, val] ⊦ (st ∪ st1[rk0, val])[rk] = (st1[rk0, val][rk])

Rule argument

[VARWITHVARSEQSARG : st0, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : store generated by ∅, [];], [CSIMPSEQ : ⊦ ¬ rk ∈ ∅])]]