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Proof step 8 from proof union-newref-02 (previous step)

⊦ r ≠ jvmref ∧ ¬ r ∈ st ∪ st0 ↔ newref(r, st) ∧ newref(r, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r ∈ st ∪ st0 ↔ r ∈ st ∨ r ∈ st0
Proof step 7:
⊦ r ≠ jvmref ∧ ¬ r ∈ st ∧ ¬ r ∈ st0 ↔ newref(r, st) ∧ newref(r, st0)

Rule argument

[emptyarg]

Additional information

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