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Proof step 6 from proof test (previous step)

is_indexkey(sk), is_fskey(sk) ⊦

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 2:
⊦
Proof step 3:
⊦ ¬ is_indexkey(fs ')
Proof step 4:
⊦ is_indexkey(i ')
Proof step 5:
⊦ ¬ is_fskey(i ')

Rule argument

[term-arg: sk]

Additional information

[[CONCRETESIMPRULES : ()]]