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Proof step 3 from proof refin-not (conclusion)

⊦ is_integervalue(val) → ¬ r ∈ val

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
is_integervalue(val), r ∈ val ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]