[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 6 from proof bytevalues-eq (
previous step
)
bytevalues(vals0) = bytevalues(vals), is_bytevalue(val1), ∀ val0. val0 ∈ vals0 ∨ val0 ∈ vals → is_bytevalue(val0), val ∈ vals0 ∨ val ∈ vals ⊦ vals0 = vals, is_bytevalue(val)
User applied rule all left
And closed the goal!
Rule argument
[EXRARG : pos: left 3, [extquanttermlist: (val)abort:F, discard:F, computed:T]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val)]]