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Proof step 5 from proof ibbis (conclusion)

⊦ is2bs(bs2is(bytes)) = bytes

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ bs2is([]) = []
Proof step 2:
⊦ is2bs([]) = []
Proof step 3:
⊦ bs2is(by ' + bytes) = b2i(by) ' + bs2is(bytes)
Proof step 4:
⊦ is2bs(i ' + ints) = i2b(i) ' + is2bs(ints)

Rule argument

[VARWITHVARSEQSARG : bytes, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : bytelist generated by [], +;], [CSIMPSEQ : ⊦ by + bytes = by ' + bytes], [CSIMPSEQ : ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1], [CSIMPSEQ : ⊦ i2b(b2i(by)) = by], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ bytes + bytes0 = bytes + bytes1 ↔ bytes0 = bytes1])]]