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Proof step 3 from proof ints2bytes-at (previous step)

m < # ints0, ∀ n. ¬ # ints0 ≤ n → (is2bs(ints0)[n]) = i2b(ints0[n]) ⊦ (is2bs(ints0)[m]) = i2b(ints0[m]), ints0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (m)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m < n → (n ≤ m ↔ false)])], [EXTRATERMS : (m)]]