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Proof step 5 from proof intvalues-append (conclusion)

⊦ intvalues(vals + vals0) = intvalues(vals) + intvalues(vals0)

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ intvalues([]) = []
Proof step 4:
∀ vals0. intvalues(vals1 + vals0) = intvalues(vals1) + intvalues(vals0) ⊦ intvalues((val + vals1) + vals0) = intvalues(val + vals1) + intvalues(vals0)

Rule argument

[VARWITHVARSEQSARG : vals, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : javavalues generated by [], +;], [CSIMPSEQ : ⊦ [] + vals = vals], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ [] + ints = ints], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1])]]