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Proof step 4 from proof intvalues-at (previous step)

m1 < # vals0, ∀ m0. ¬ # vals0 ≤ m0 → (intvalues(vals0)[m0]) = vals0[m0] .intval ⊦ (intvalues(vals0)[m1]) = vals0[m1] .intval, vals0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (m1)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m < n → (n ≤ m ↔ false)])], [EXTRATERMS : (m1)]]