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Proof step 3 from proof isbytelist-all (
previous step
)
is_bytevalue(val), is_bytelist(vals0), val0 ∈ vals0, ∀ val. val ∈ vals0 → is_bytevalue(val) ⊦ is_bytevalue(val0)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
[EXRARG : pos: left 4, [QUANTTERMLIST : (val0)]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val0)]]