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Proof step 4 from proof mkjavavalues-append-01 (previous step)

∀ bytes0. mkjavavalues(bytes1 + bytes0) = mkjavavalues(bytes1) + mkjavavalues(bytes0) ⊦ mkjavavalues((by + bytes1) + bytes0) = mkjavavalues(by + bytes1) + mkjavavalues(bytes0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ mkjavavalues(by ' + bytes) = byteval(by) ' + mkjavavalues(bytes)
Proof step 3:
∀ bytes0. mkjavavalues(bytes1 + bytes0) = mkjavavalues(bytes1) + mkjavavalues(bytes0) ⊦ mkjavavalues(bytes1 + bytes0) = mkjavavalues(bytes1) + mkjavavalues(bytes0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ vals + vals0 = vals + vals1 ↔ vals0 = vals1], [CSIMPSEQ : ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1], [CSIMPSEQ : ⊦ by + bytes = by ' + bytes])]]