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Proof step 5 from proof mkjavavalues-append (previous step)

∀ refs0. mkjavavalues(refs1 + refs0) = mkjavavalues(refs1) + mkjavavalues(refs0) ⊦ mkjavavalues(r + (refs1 + refs0)) = mkjavavalues(r + refs1) + mkjavavalues(refs0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ mkjavavalues(r ' + refs) = refval(r) ' + mkjavavalues(refs)
Proof step 4:
∀ refs0. mkjavavalues(refs1 + refs0) = mkjavavalues(refs1) + mkjavavalues(refs0) ⊦ mkjavavalues(refs1 + refs0) = mkjavavalues(refs1) + mkjavavalues(refs0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ vals + vals0 = vals + vals1 ↔ vals0 = vals1], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]