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Proof step 7 from proof mkjavavalues-restn (previous step)

n ≤ 1 + # bytes0, ∀ n0. ¬ # bytes0 < n0 → restn(n0, mkjavavalues(bytes0)) = mkjavavalues(restn(n0, bytes0)) ⊦ restn(n, byteval(by) ' + mkjavavalues(bytes0)) = mkjavavalues(restn(n - 1, bytes0)), n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
n = m + 1, n ≤ 1 + # bytes0, ∀ n0. ¬ # bytes0 < n0 → restn(n0, mkjavavalues(bytes0)) = mkjavavalues(restn(n0, bytes0)) ⊦ restn(n, byteval(by) ' + mkjavavalues(bytes0)) = mkjavavalues(restn(m, bytes0)), n = 0

Rule argument

[speclemmaarg: n ≠ 0 ,m = n - 1 ↔ n = m + 1 ,[n, m] → [n, m] ,T ,nat , ,elim-pred-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1])], [EXTRATERMS : (n, m)]]