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Proof step 10 from proof nonnullrefs-append (previous step)

¬ is_referencevalue(val) ∨ val .refval = jvmref, ¬ is_referencevalue(val) ∨ val .refval = jvmref, ∀ vals0. (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs ⊦ (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (vals0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (vals0)]]