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Proof step 13 from proof nonnullrefs-append (previous step)

∀ vals0. (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs ⊦ ((val + vals1) + vals0) .nonnullrefs = (val + vals1) .nonnullrefs + vals0 .nonnullrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
∀ vals0. (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs ⊦ ((val ' + vals1) + vals0) .nonnullrefs = (val ' + vals1) .nonnullrefs + vals0 .nonnullrefs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, javavalues, c, ⊦ val + vals = val ' + vals])]]