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Proof step 5 from proof nonnullrefs-append (previous step)

val = refval(r), is_referencevalue(val), ∀ vals0. (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs ⊦ r = jvmref, (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ vals0. (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs ⊦ r = jvmref, (vals1 + vals0) .nonnullrefs = vals1 .nonnullrefs + vals0 .nonnullrefs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))])]]