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Proof step 39 from proof nonnullrefs-dups-firstoc (previous step)

dups(vals0 .nonnullrefs) ↔ (∃ r, vals, vals1, vals2. vals0 = vals + refval(r) ' + vals1 + refval(r) ' + vals2 ∧ r ≠ jvmref ∧ ¬ refval(r) ∈ vals ∧ ¬ refval(r) ∈ vals1) ⊦ dups((val ' + vals0) .nonnullrefs) ↔ (∃ r, vals, vals1, vals2. val ' + vals0 = vals + refval(r) ' + vals1 + refval(r) ' + vals2 ∧ r ≠ jvmref ∧ ¬ refval(r) ∈ vals ∧ ¬ refval(r) ∈ vals1)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: nonnullrefs-no antecedent: succedent: ¬ is_referencevalue(val) ∨ val .refval = jvmref → (val ' + vals) .nonnullrefs = vals .nonnullrefs substlist: [vals, val] → [vals0, val] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0, 1, 0, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (vals0, val)]]