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Proof step 20 from proof nonnullrefs-dups (previous step)

n ≠ 0, vals0[n -1] = refval(r), n ≤ # vals0 ⊦ 0 = n, r = jvmref, dups(vals0 .nonnullrefs), r ∈ vals0 .nonnullrefs, ∃ r1, m0, n0. vals0[m0] = refval(r1) ∧ vals0[n0] = refval(r1) ∧ r1 ≠ jvmref ∧ m0 ≠ n0 ∧ ¬ # vals0 ≤ m0 ∧ ¬ # vals0 ≤ n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
vals0[n - 1] = refval(r), n ≤ # vals0 ⊦ r = jvmref, n = 0, dups(vals0 .nonnullrefs), r ∈ vals0 .nonnullrefs, ∃ r1, m0, n0. vals0[m0] = refval(r1) ∧ vals0[n0] = refval(r1) ∧ r1 ≠ jvmref ∧ m0 ≠ n0 ∧ ¬ # vals0 ≤ m0 ∧ ¬ # vals0 ≤ n0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat, , pred-03, ⊦ n -1 = n - 1])]]