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Proof step 29 from proof nonnullrefs-dups (previous step)

vals0[m1] = refval(r), vals0[m] = refval(r), m1 < # vals0, m < # vals0 ⊦ r0 = jvmref, vals0 = [], r = jvmref, m1 = m, dups(vals0 .nonnullrefs), r0 ∈ vals0 .nonnullrefs, ∃ r1, m0, n0. vals0[m0] = refval(r1) ∧ vals0[n0] = refval(r1) ∧ r1 ≠ jvmref ∧ m0 ≠ n0 ∧ ¬ # vals0 ≤ m0 ∧ ¬ # vals0 ≤ n0

User applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 7, [extquanttermlist: (r, m1, m)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat, , ls-le-simp, ⊦ m < n → (n ≤ m ↔ false)])], [EXTRATERMS : (r, m1, m)]]