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Proof step 50 from proof nonnullrefs-dups (previous step)

val ' + vals0 ≠ [] ∧ n ≠ 0, vals0[m1] = refval(r), ((val ' + vals0) .rest)[n - 1] = refval(r), m1 < # vals0, n ≤ # vals0, ¬ is_referencevalue(val) ∨ val .refval = jvmref ⊦ r = jvmref, m1 + 1 = n, vals0 = [], dups(vals0 .nonnullrefs), ∃ r0, m0, n0. vals0[m0] = refval(r0) ∧ vals0[n0] = refval(r0) ∧ r0 ≠ jvmref ∧ m0 ≠ n0 ∧ ¬ # vals0 ≤ m0 ∧ ¬ # vals0 ≤ n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
vals0[m1] = refval(r), vals0[n - 1] = refval(r), m1 < # vals0, n ≤ # vals0, ¬ is_referencevalue(val) ∨ val .refval = jvmref ⊦ r = jvmref, m1 + 1 = n, vals0 = [], n = 0, dups(vals0 .nonnullrefs), ∃ r0, m0, n0. vals0[m0] = refval(r0) ∧ vals0[n0] = refval(r0) ∧ r0 ≠ jvmref ∧ m0 ≠ n0 ∧ ¬ # vals0 ≤ m0 ∧ ¬ # vals0 ≤ n0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat-basic2, , c, ⊦ m + n = n + m], [CSIMPNAMEDSEQ : nat-basic2, , a, ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPNAMEDSEQ : list, javavalues, e-01, ⊦ val ' + vals ≠ []], [CSIMPNAMEDSEQ : list, javavalues, a, ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPNAMEDSEQ : list, javavalues, c-07, ⊦ (val ' + vals) .rest = vals])]]