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Proof step 58 from proof nonnullrefs-dups (previous step)

dups(vals0 .nonnullrefs) ↔ (∃ r, m, n. vals0[m] = refval(r) ∧ vals0[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ m < # vals0 ∧ n < # vals0) ⊦ dups((val ' + vals0) .nonnullrefs) ↔ (∃ r, m, n. (val ' + vals0)[m] = refval(r) ∧ (val ' + vals0)[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ ¬ # vals0 < m ∧ ¬ # vals0 < n)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ is_referencevalue(val) ∨ val .refval = jvmref → (val ' + vals) .nonnullrefs = vals .nonnullrefs
Proof step 42:
¬ (¬ is_referencevalue(val) ∨ val .refval = jvmref), dups(vals0 .nonnullrefs) ↔ (∃ r, m, n. vals0[m] = refval(r) ∧ vals0[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ m < # vals0 ∧ n < # vals0) ⊦ dups((val ' + vals0) .nonnullrefs) ↔ (∃ r, m, n. (val ' + vals0)[m] = refval(r) ∧ (val ' + vals0)[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ ¬ # vals0 < m ∧ ¬ # vals0 < n)
Proof step 57:
¬ is_referencevalue(val) ∨ val .refval = jvmref, dups(vals0 .nonnullrefs) ↔ (∃ r, m, n. vals0[m] = refval(r) ∧ vals0[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ m < # vals0 ∧ n < # vals0) ⊦ dups(vals0 .nonnullrefs) ↔ (∃ r, m, n. (val ' + vals0)[m] = refval(r) ∧ (val ' + vals0)[n] = refval(r) ∧ r ≠ jvmref ∧ m ≠ n ∧ ¬ # vals0 < m ∧ ¬ # vals0 < n)

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: nonnullrefs-no antecedent: succedent: ¬ is_referencevalue(val) ∨ val .refval = jvmref → (val ' + vals) .nonnullrefs = vals .nonnullrefs substlist: [vals, val] → [vals0, val] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0, 1, 0, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (vals0, val)]]