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Proof step 13 from proof nonnullrefs-in-firstoc (previous step)

r ∈ vals0 .nonnullrefs → vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals ⊦ r0 = jvmref, r = jvmref, r ≠ r0 ∧ ¬ r ∈ vals0 .nonnullrefs, ∃ vals, vals1. refval(r0) ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals

User applied rule cut formula

And obtained the following new goals

Proof step 8:
r = r0, r ∈ vals0 .nonnullrefs → vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals ⊦ r0 = jvmref, r = jvmref, r ≠ r0 ∧ ¬ r ∈ vals0 .nonnullrefs, ∃ vals, vals1. refval(r0) ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals
Proof step 12:
r ∈ vals0 .nonnullrefs → vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals ⊦ r = r0, r0 = jvmref, r = jvmref, r ≠ r0 ∧ ¬ r ∈ vals0 .nonnullrefs, ∃ vals, vals1. refval(r0) ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals

Rule argument

[fma-arg: r = r0]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (r = r0)]]