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Proof step 16 from proof nonnullrefs-in-firstoc (previous step)

val = refval(r0), is_referencevalue(val), r ∈ vals0 .nonnullrefs → r ≠ jvmref ∧ vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals ⊦ r0 = jvmref, r ≠ jvmref ∧ (∃ vals, vals1. val ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals), r ≠ r0 ∧ ¬ r ∈ vals0 .nonnullrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
r ∈ vals0 .nonnullrefs → r ≠ jvmref ∧ vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals ⊦ r0 = jvmref, r ≠ jvmref ∧ (∃ vals, vals1. refval(r0) ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals), r ≠ r0 ∧ ¬ r ∈ vals0 .nonnullrefs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))])]]