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Proof step 25 from proof nonnullrefs-in-firstoc (previous step)

∀ r. r ∈ vals0 .nonnullrefs → r ≠ jvmref ∧ (∃ vals2, vals1. vals0 = vals2 + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals2) ⊦ ¬ r ∈ val ' .nonnullrefs ∧ ¬ r ∈ vals0 .nonnullrefs, r ≠ jvmref ∧ (∃ vals, vals1. val ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals)

User applied rule all left

And obtained the following new goals

Proof step 24:
r ∈ vals0 .nonnullrefs → r ≠ jvmref ∧ (∃ vals2, vals1. vals0 = vals2 + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals2) ⊦ ¬ r ∈ val ' .nonnullrefs ∧ ¬ r ∈ vals0 .nonnullrefs, r ≠ jvmref ∧ (∃ vals, vals1. val ' + vals0 = vals + refval(r) ' + vals1 ∧ ¬ refval(r) ∈ vals)

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r)]]