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Proof step 13 from proof nonnullrefs-in (previous step)

vals0[m0] = refval(r), m0 < # vals0, ∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r = jvmref, r1 = jvmref, r = r1, vals0 = [], r ∈ vals0 .nonnullrefs

User applied rule all left

And obtained the following new goals

Proof step 12:
vals0[m0] = refval(r), m0 < # vals0, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r = jvmref, r1 = jvmref, r = r1, vals0 = [], r ∈ vals0 .nonnullrefs

Rule argument

[EXRARG : pos: left 3, [extquanttermlist: (r)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r)]]