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Proof step 19 from proof nonnullrefs-in (previous step)

∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r1 = jvmref, r = r1 ↔ r ≠ jvmref ∧ (∃ m. (refval(r1) ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m), r ∈ vals0 .nonnullrefs

User applied rule cut formula

And obtained the following new goals

Proof step 9:
r = r1, ∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r1 = jvmref, r = r1 ↔ r ≠ jvmref ∧ (∃ m. (refval(r1) ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m), r ∈ vals0 .nonnullrefs
Proof step 18:
∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r = r1, r1 = jvmref, r = r1 ↔ r ≠ jvmref ∧ (∃ m. (refval(r1) ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m), r ∈ vals0 .nonnullrefs

Rule argument

[fma-arg: r = r1]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (r = r1)]]