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Proof step 23 from proof nonnullrefs-in (previous step)

is_referencevalue(val), ∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ val .refval = jvmref, r = val .refval ∨ r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 22:
val = refval(r1), is_referencevalue(val), ∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r1 = jvmref, r = r1 ∨ r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)

Rule argument

[x0lemmaarg: spec-name: javavalue instance-name: lemma-name: elim-13 antecedent: succedent: is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) substlist: [val, r] → [val, r1] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r1)]]