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Proof step 37 from proof nonnullrefs-in (previous step)

∀ r. r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ ¬ # vals0 ≤ m) ⊦ r ∈ (val + vals0) .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. (val + vals0)[m] = refval(r) ∧ ¬ # (val + vals0) ≤ m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
∀ r0. r0 ∈ vals0 .nonnullrefs ↔ r0 ≠ jvmref ∧ (∃ m. vals0[m] = refval(r0) ∧ m < # vals0) ⊦ r ∈ (val ' + vals0) .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat, , lels-01, ⊦ ¬ m ≤ n ↔ n < m], [CSIMPNAMEDSEQ : nat-basic2, , c, ⊦ m + n = n + m], [CSIMPNAMEDSEQ : nat-basic2, , a, ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPNAMEDSEQ : nat, , succ-01, ⊦ m + 1 ≤ n ↔ m < n], [CSIMPNAMEDSEQ : list, javavalues, a, ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPNAMEDSEQ : list, javavalues, len-02, ⊦ # val ' = 0 +1], [CSIMPNAMEDSEQ : list, javavalues, len, ⊦ # (vals + vals0) = # vals + # vals0], [CSIMPNAMEDSEQ : list, javavalues, c, ⊦ val + vals = val ' + vals])]]