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Proof step 5 from proof nonnullrefs-in (previous step)

r ∈ vals0 .nonnullrefs, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r1 = jvmref, r ≠ jvmref ∧ (∃ m. (refval(r1) ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
vals0[m] = refval(r), m < # vals0, r ∈ vals0 .nonnullrefs ⊦ r = jvmref, r1 = jvmref, vals0 = [], ∃ m. (refval(r1) ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list-data, javavalues, l, ⊦ # vals = 0 ↔ vals = []], [CSIMPNAMEDFORWARD : nat-basic1, , f, ⊦ m < n → n ≠ 0], [CSIMPNAMEDSEQ : nat, , lels, ⊦ ¬ m < n ↔ n ≤ m])]]