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Proof step 3 from proof vals2int-one (conclusion)

⊦ vals2ints(val ') = val2int(val) '

User applied rule insert lemma

And obtained the following new goals

Proof step 1:
⊦ vals2ints(val ' + vals) = val2int(val) + vals2ints(vals)
Proof step 2:
⊦ vals2ints([]) = []

Rule argument

[LEMMAARG : vals2ints-rec, [val, vals] → [val, []]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ vals + [] = vals], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ i + ints = i ' + ints], [CSIMPSEQ : ⊦ ints + [] = ints], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1])], [EXTRATERMS : (val, [])]]