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Proof step 30 from proof cont-monotone (
previous step
)
∃ n. (n = 0 ⊃ S0;S)(x0), f(S0)(x), S0 ⊆ S, f(λ x0. ∃ n. (n = 0 ⊃ S0;S)(x0))(x) ⊦ S(x0), f(S)(x)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 31
:
(n = 0 ⊃ S0;S)(x0), f(S0)(x), S0 ⊆ S, f(λ x0. ∃ n. (n = 0 ⊃ S0;S)(x0))(x) ⊦ S(x0), f(S)(x)
Rule argument
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