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Proof step 1 from proof iterate-is-fix (conclusion)

cont(f) ⊦ μ(f)(x) ↔ (∃ n. ((f ^ n))(λ x. false)(x))

User applied rule case distinction

And obtained the following new goals

Proof step 2:
μ(f)(x), cont(f) ⊦ ∃ n. ((f ^ n))(λ x. false)(x)
Proof step 12:
∃ n. ((f ^ n))(λ x. false)(x), cont(f) ⊦ μ(f)(x)

Rule argument

pos: right 1

Additional information