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Proof step 11 from proof iterate-is-fix (previous step)

(λ x0. ∃ n. ((f ^ n))(λ x. false)(x0)) = f(λ x0. ∃ n. ((f ^ n))(λ x. false)(x0)), cont(f), f(λ x. ∃ n. ((f ^ n))(λ x. false)(x))(x0) ⊦ ∃ n. ((f ^ n))(λ x. false)(x0), ∃ n. ((f ^ n))(λ x. false)(x)

User applied rule expand left

And closed the goal!

Rule argument

pos: left 1 terms: x0 abort: F discard: T computed: F

Additional information

Used terms: x0