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Proof step 4 from proof at-copy (previous step)

m0 < # ar1 ⊦ # ar1 = 0, ar1[m0] = (m0 < n0 ∨ n0 ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0])

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat