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Proof step 7 from proof at-copy (previous step)

m0 < # ar1, ∀ m0, ar1, ar0, n, n0. m0 < # ar1 → copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) ∨ # ar1 = 0 ⊦ m0 = n0 + m1, # ar1 = 0, copy(ar0, n, ar1, n0, m1)[n0 + m1, ar0[n + m1]][m0] = (m0 < n0 ∨ n0 + m1 < m0 ⊃ ar1[m0];ar0[m0 + n - n0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
m0 < # ar1, ∀ m0, ar1, ar0, n, n0. m0 < # ar1 → copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) ∨ # ar1 = 0 ⊦ m0 = n0 + m1, # ar1 = 0, copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 < m0 ⊃ ar1[m0];ar0[m0 + n - n0])

Rule argument

Additional information

Used simplifier rules: Put-other: ⊦ m ≠ n → ar[n, a][m] = ar[m]; from specification array