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Proof step 9 from proof at-copy (previous step)

m0 < n0 ∨ n0 + m1 < m0, m0 < # ar1, ∀ m0, ar1, ar0, n, n0. m0 < # ar1 → copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) ∨ # ar1 = 0 ⊦ copy(ar0, n, ar1, n0, m1)[m0] = ar1[m0], m0 = n0 + m1, # ar1 = 0

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m0, ar1, ar0, n, n0 abort: F discard: F computed: T

Additional information

Used simplifier rules: lels-02: ⊦ m ≠ n → (m ≤ n ↔ m < n); from specification nat Used terms: m0, ar1, ar0, n, n0