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Proof step 1 from proof copy-append (conclusion)

⊦ copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0) = copy(ar0, n, ar1, n1, m0 + m1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n])
Proof step 3:
⊦ # copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0) = # copy(ar0, n, ar1, n1, m0 + m1) ∧ (∀ n0. n0 < # copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0) → copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0)[n0] = copy(ar0, n, ar1, n1, m0 + m1)[n0])

Rule argument

spec: array inst: name: Extension seq: ⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n]) subst: [ar2, ar1] → [copy(ar0, n, ar1, n1, m0 + m1), copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0)] flags: rewrite

Additional information

Used terms: copy(ar0, n, ar1, n1, m0 + m1), copy(ar0, n + m1, copy(ar0, n, ar1, n1, m1), n1 + m1, m0)