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Proof step 2 from proof copy-rec (previous step)

⊦ copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]] = copy(ar, m + 1, ar0, m0 + 1, n)[m0, ar[m]]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n])
Proof step 4:
⊦ # copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]] = # copy(ar, m + 1, ar0, m0 + 1, n)[m0, ar[m]] ∧ (∀ n0. n0 < # copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]] → copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]][n0] = copy(ar, m + 1, ar0, m0 + 1, n)[m0, ar[m]][n0])

Rule argument

spec: array inst: name: Extension seq: ⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n]) subst: [ar2, ar1] → [copy(ar, m + 1, ar0, m0 + 1, n)[m0, ar[m]], copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]]] flags: rewrite

Additional information

Used terms: copy(ar, m + 1, ar0, m0 + 1, n)[m0, ar[m]], copy(ar, m, ar0, m0, n)[m0 + n, ar[m + n]]