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Proof step 8 from proof copy-subarray1-elim (previous step)

n = n2 + m0, m0 < # ar1, n < m0 + m1, m0 ≤ n, n < # ar1, m + m1 ≤ n1, n0 + n1 ≤ # ar0 ⊦ m0 + m1 = 0, copy(ar0, n0, mkarray(n1), 0, n1)[n2 + m] = ar0[n2 + n0 + m], # ar1 = 0, m1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
n2 + m0 < # ar1, m + m1 ≤ n1, n0 + n1 ≤ # ar0, m0 < # ar1, n2 < m1 ⊦ m0 + m1 = 0, copy(ar0, n0, mkarray(n1), 0, n1)[n2 + m] = ar0[n2 + n0 + m], # ar1 = 0, m1 = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lep: ⊦ m ≤ m + n; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%l: ⊦ m + n < m + n0 ↔ n < n0; from specification nat-basic2