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Proof step 3 from proof idexcept-trans (previous step)

# ar0 = # ar2, # ar1 = # ar2, m < # ar2, ∀ m. m < # ar2 ∧ m ≠ n → ar0[m] = ar1[m], m < # ar2 ∧ m ≠ n → ar1[m] = ar2[m], ∀ m. m < # ar2 ∧ m ≠ n → ar1[m] = ar2[m] ⊦ # ar2 = 0, m = n, ar0[m] = ar2[m]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
# ar0 = # ar2, # ar1 = # ar2, ar1[m] = ar2[m], m < # ar2, ∀ m. m < # ar2 ∧ m ≠ n → ar1[m] = ar2[m], ∀ m. m < # ar2 ∧ m ≠ n → ar0[m] = ar1[m] ⊦ # ar2 = 0, m = n, ar0[m] = ar2[m]

Proof step 3 from proof idexcept-trans (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information