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Proof step 14 from proof rev-at-h (previous step)

# ar = n2 + n1 + 1, n1 < # ar, # rev(ar, n1) ≤ n1, # rev(ar, n1) < # ar, # rev(ar, n1) ≤ n2 + n1, ∀ ar, n0, m. # ar = n0 + m + 1 ∧ m < n1 ∧ n1 ≤ # ar ∧ m < # ar → # ar = 0 ∨ rev(ar, n1)[m] = ar[n0] ∨ n1 = 0 ⊦ rev(ar, n1)[n1, ar[n2]][n1] = ar[n2], # ar = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: rev-size-h seq: ⊦ n ≤ # ar → # rev(ar, n) = # ar subst: [n, ar] → [n1, ar] flags: rewrite, current

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat%le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used terms: n1, ar