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Proof step 8 from proof rev-at (previous step)

n < # ar ∧ # ar ≤ # ar, # ar = n0 + n + 1, n < # ar ⊦ # ar = 0, ar[# ar - n + 1] = ar[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# ar = n0 + n + 1, n < # ar ⊦ # ar = 0, ar[# ar - n + 1] = ar[n0]

Rule argument

Additional information

Used simplifier rules: ler: ⊦ m ≤ m; from specification nat