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Proof step 6 from proof rev-rev (previous step)

n < # rev(ar), n < # ar ⊦ rev(ar)[# rev(ar) - n + 1] = ar[n], # ar = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
n < # ar ⊦ # ar = 0, rev(ar)[# ar - n + 1] = ar[n]

Rule argument

Additional information

Used simplifier rules: rev-size: ⊦ # rev(ar) = # ar;