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Proof step 3 from proof rev-size-h (previous step)

∀ ar. n0 ≤ # ar → # rev(ar, n0) = # ar, n0 +1 ≤ # ar ⊦ # rev(ar, n0 +1) = # ar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
n0 < # ar, ∀ ar. n0 ≤ # ar → # rev(ar, n0) = # ar ⊦ # rev(ar, n0) = # ar, # ar = 0

Rule argument

Additional information

Used simplifier rules: rev-rec: ⊦ n < # ar → rev(ar, n + 1) = rev(ar, n)[n, ar[# ar - n + 1]];%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%Size-put: ⊦ # ar[n, a] = # ar; from specification array%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat%succ: ⊦ m +1 = m + 1; from specification nat-basic2