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Proof step 1 from proof subarray-copy-elim-exact (conclusion)

m1 + n ≤ # ar1 ⊦ subarray(copy(ar0, m0, ar1, m1, n), m1, n) = subarray(ar0, m0, n)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
m1 + n ≤ # ar1 ⊦ n1 ≤ n → subarray(copy(ar0, m0, ar1, m1, n), m1, n1) = subarray(ar0, m0, n1)

Rule argument

spec: inst: name: subarray-copy-elim seq: m1 + n ≤ # ar1 ⊦ n1 ≤ n → subarray(copy(ar0, m0, ar1, m1, n), m1, n1) = subarray(ar0, m0, n1) subst: [n1, n, m1, ar1, m0, ar0] → [n, n, m1, ar1, m0, ar0] flags: rewrite, current

Additional information

Used simplifier rules: Subarray: ⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n);%ler: ⊦ m ≤ m; from specification nat Used terms: n, n, m1, ar1, m0, ar0