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Proof step 2 from proof subarray-copy-elim (previous step)

n1 ≤ n, m1 + n ≤ # ar1 ⊦ copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1) = copy(ar0, m0, mkarray(n1), 0, n1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n])
Proof step 4:
n1 ≤ n, m1 + n ≤ # ar1 ⊦ # copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1) = # copy(ar0, m0, mkarray(n1), 0, n1) ∧ (∀ n0. n0 < # copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1) → copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1)[n0] = copy(ar0, m0, mkarray(n1), 0, n1)[n0])

Rule argument

spec: array inst: name: Extension seq: ⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n]) subst: [ar2, ar1] → [copy(ar0, m0, mkarray(n1), 0, n1), copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1)] flags: rewrite

Additional information

Used terms: copy(ar0, m0, mkarray(n1), 0, n1), copy(copy(ar0, m0, ar1, m1, n), m1, mkarray(n1), 0, n1)