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Proof step 7 from proof subarray-copy-elim (previous step)

n0 < # mkarray(n1), n0 < n, n0 < n1, m1 + n ≤ # ar1, n1 ≤ n ⊦ n1 = 0, (n0 < 0 ∨ 0 + n1 ≤ n0 ⊃ mkarray(n1)[n0];copy(ar0, m0, ar1, m1, n)[n0 + m1 - 0]) = copy(ar0, m0, mkarray(n1), 0, n1)[n0], n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n0 < n, m1 + n ≤ # ar1, n1 ≤ n, n0 < n1 ⊦ n = 0, n1 = 0, copy(ar0, m0, ar1, m1, n)[n0 + m1] = ar0[n0 + m0]

Rule argument

Additional information

Used simplifier rules: at-copy: ⊦ m0 < # ar1 → copy(ar0, n, ar1, n0, m)[m0] = (m0 < n0 ∨ n0 + m ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]);%Size-mkarray: ⊦ # mkarray(n) = n; from specification array%sub-base: ⊦ m - 0 = m; from specification nat%ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-base: ⊦ n + 0 = n; from specification nat-basic2%zero-01: ⊦ ¬ m < 0; from specification nat-basic1