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Proof step 1 from proof subarray-copy-lower (conclusion)

n1 + n2 ≤ m0, m0 + m1 ≤ # ar ⊦ subarray(copy(ar0, n0, ar, n1, n2), m0, m1) = subarray(ar, m0, m1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n1 + n2 ≤ m0, m0 + m1 ≤ # ar ⊦ copy(copy(ar0, n0, ar, n1, n2), m0, mkarray(m1), 0, m1) = copy(ar, m0, mkarray(m1), 0, m1)

Rule argument

Additional information

Used simplifier rules: Subarray: ⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n);