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Proof step 3 from proof subarray-copy (previous step)

n1 = n3 + m0, m0 + m1 ≤ # ar1, m0 ≤ n1 ⊦ copy(copy(ar0, n0, ar1, n1, n2), m0, mkarray(m1), 0, m1) = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
m0 + m1 ≤ # ar1 ⊦ copy(copy(ar0, n0, ar1, n3 + m0, n2), m0, mkarray(m1), 0, m1) = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat